4x^2(x^2-1)+5x(x^2-1)+(x^2-1)=0

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Solution for 4x^2(x^2-1)+5x(x^2-1)+(x^2-1)=0 equation: 


Simplifying
4x2(x2 + -1) + 5x(x2 + -1) + (x2 + -1) = 0

Reorder the terms:
4x2(-1 + x2) + 5x(x2 + -1) + (x2 + -1) = 0
(-1 * 4x2 + x2 * 4x2) + 5x(x2 + -1) + (x2 + -1) = 0
(-4x2 + 4x4) + 5x(x2 + -1) + (x2 + -1) = 0

Reorder the terms:
-4x2 + 4x4 + 5x(-1 + x2) + (x2 + -1) = 0
-4x2 + 4x4 + (-1 * 5x + x2 * 5x) + (x2 + -1) = 0
-4x2 + 4x4 + (-5x + 5x3) + (x2 + -1) = 0

Reorder the terms:
-4x2 + 4x4 + -5x + 5x3 + (-1 + x2) = 0

Remove parenthesis around (-1 + x2)
-4x2 + 4x4 + -5x + 5x3 + -1 + x2 = 0

Reorder the terms:
-1 + -5x + -4x2 + x2 + 5x3 + 4x4 = 0

Combine like terms: -4x2 + x2 = -3x2
-1 + -5x + -3x2 + 5x3 + 4x4 = 0

Solving
-1 + -5x + -3x2 + 5x3 + 4x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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